A stone projected at an angle of 60...
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A stone projected at an angle of 609 from the ground level strikes at an angle of 30° on the roof of a building of height 'h'. Then the speed of projection of the stone is : (A) 2gh (B) V6gh (D) Jgh 60° TI 3gh

JEE/Engineering Exams
Physics
Solution
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Components of ( x ) is ( 4 cos 60^{circ} ) and ( y ) is ( 4 sin 60^{circ} ) At h height distance, ( tan 30^{circ}=mathrm{V} mathrm{y} / mathrm{ucos} 60^{circ} ) ( mathrm{Vy}=mathrm{u} / 2 sqrt{3} ) Distance in ( mathrm{y} ) - direction : ( V y^{2}-(u sin 60)^{2}=2 a s ) ( (mathrm{u} / 2 sqrt{3})^{2}-(mathrm{u} sqrt{3} / 2)^{2}=-2 mathrm{g} mathrm{s} ) By this ,we get ( u=sqrt{3} g h )
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