Question

Now, let us use Euclid's algorithm to find their H.C.F. We have:
[
begin{array}{l}
420=130 times 3+30
130=30 times 4+10
30=10 times 3+0
end{array}
]
So, the H.C.F of 420 and 130 is ( 10 . )
Therefore, the sweetseller can make stacks of 10 for both kinds of barfi.

# A sweetseller has 420 kaju barfis and 130 badam barfis. She wants to stack them in such a way that each stack has the same number, and they take up the least area of the tray. What is the maximum number of barfis that can be placed in each stack for this purpose? Se

Solution