Question

( U=30 m / s, v=50 m / s )
total distance ( =200+300=500 m )
( v^{2}-u^{2}=2 a s )
( (50)^{2}-(30)^{2}=2 times 500 times a )
( 1600=1000 a )
( a=0.16 m / s^{2} )
( v=u+a^{*} t )
( 50=30+0.16 t )
( 0.16 t=20 )
( t=20 / 0.16=125 s e c )

# A train 200 m long enters at 5 m/s and exits at 3 m/s from a bridge 300 m long. The time taken by it is (1) 125 s (2) 500 s (3) 260 S (4) 50 s

Solution