Question
( a: b=c: d=e: f=1: 2 )
( (3 a+5 c+7 e):(3 b+5 d+7 f)=? )
( frac{a}{b}=frac{c}{d}=frac{e}{f}=frac{1}{2} )
( frac{3 a}{3 b}=frac{5 c}{5 d}=frac{7 e}{7 p}=frac{1}{2} )
( frac{3 a+5 c+7 e}{3 b+5 d+7 f}=frac{1}{2}=1: 2 )

ab codeid - 1:2 (30+50+20) : (36+5 d +1f) .
Solution
