al Solution of ** 2 * (1) * • (-6, -1) (1.1) ue, en (B) * (-4,-2) u (1-1) u (4,4) (0)3 € (-4,-3) u (1 302,4

$$\begin{gathered} \frac{x-2}{x+2}>\frac{2x-3}{4x-1} \\ \Rightarrow \frac{x-2}{x+2}-\frac{2x-3}{4x-1}>0 \\ \Rightarrow \frac{\left(x-2\right)(4x-1)-(2x-3)(x+2)}{(x+2)(4x-1)}>0 \\ \Rightarrow \frac{4x^2-x-8x+2-2x^2-4x+3x+6}{(x+2)(4x-1)}>0 \\ \Rightarrow \frac{2x^2-10x+8}{(x+2)(4x-1)}>0 \\ \Rightarrow \frac{2x^2-2x-8x+8}{(x+2)(4x-1)}>0\Rightarrow \frac{2x(x-1)-8(x-1)}{(x+2)(4x-1)}>0 \\ \Rightarrow \frac{(2x-8)(x-1)}{(x+2)(4x-1)}>0 \\ x\in (-\infty ,-2)\cup \left(\frac{1}{4},1\right)\cup \left(4,\infty \right) \\ \mathit{A}\mathit{n}\mathit{s}\mathbf{ }\mathbf{\left(}\mathit{B}\mathbf{\right)} \end{gathered}$$