Question

Mslaily = '/ by meight X density x 10
[
begin{array}{l}
=frac{13 times 1.02 times 10}{98}
=frac{132.6}{98}=1.35 mathrm{M}
end{array}
]
13% solution by weight means anat isg of solute is exter dissolucd un ( 87 mathrm{g} ) for soluent
Nemaliliy ( x ) eq. wit = molurity ( x ) wol. wet ( N times frac{98}{2}=1.35 times 98 )
[
begin{array}{c}
N=1.35 times 2=2.70 mathrm{N}
N_{1} V_{1}=N_{2} V_{2}
100 times 2 cdot 70 N=1.5 mathrm{N} times V_{2}
sigma_{2}=180 mathrm{mL}
end{array}
]
6
&o the aid should be diluted vpto is
ML tr Mepare 1.5 N soln

# All star marked Questions are multiple correct with one or more than one Answer. 0.1 What is the molarity and molality of a 13% solution (by weight) of sulphuric acid with a density of 1.02 g/ml To what volume should 100 ml of this acid be diluted in order to prepare a 1.5 N solution?

Solution