Question

Mslaily = '/. by meyht X density x lo
[
begin{array}{l}
=frac{13 times 1.02 times 10}{98}
=frac{132 cdot 6}{98}=1.35 mathrm{M}
end{array}
]
( 13 % ) solution by weight means asat is a of solute is mat dissomed in ( 87 mathrm{g} ) for soluct
Nemalily ( x ) eq. wit = molurity ( x ) wol. wet ( N times frac{98}{2}=1.35 times 98 )
[
begin{array}{c}
N=1.35 times 2=2.70 mathrm{N}
N_{1} V_{1}=N_{2} V_{2}
100 times 2.70 N=1.5 mathrm{N} times V_{2}
V_{2}=180 mathrm{mL}
end{array}
]
Go the alid should be diluted upto is 80 ML tr Mepare 1.5 N soln

# all star marked Questions are multiple correct with one or more than one Answer. What is the molarity and molality of a 13% solution (by weight) of sulphuric acid with a density of 1.02 g/ml To what volume should 100 ml of this acid be diluted in order to prepare a 1.5 N solution? [IIT-1978) ✓

Solution