Question

# An ideal gas is initially at temperature ( T ) and volume ( V ). Its volume is increased by ( Delta V ) due to an increase in temperature ( triangle ) T, pressure remaining constant. The quantity ( delta=frac{Delta V}{(V Delta T)} ) varies with temperature as

Solution

Correct Option (c)

Explanation:

From ideal gas equation ( mathrm{PV}=mathrm{RT} )

or ( P Delta V=R Delta T )

Dividing equation (ii) by (i) we get ( Delta V / V ) ( =Delta mathrm{T} / mathrm{T}=Delta mathrm{V} / mathrm{V} Delta mathrm{T}=1 / T=delta )

( therefore quad delta=1 / mathrm{t} . ) So the graph between ( delta ) and ( T )

will be rectangular hyperbola.