Ass + x+ If then find value of x®
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Ass + x+ If then find value of x®

JEE/Engineering Exams
Maths
Solution
109
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( x+frac{1}{x}=sqrt{3} ) ( left(x+frac{1}{x}right)^{3}=(sqrt{3})^{3} ) ( x^{3}+frac{1}{x^{3}}+3(x)left(frac{1}{x}right)left(x+frac{1}{x}right)=3 sqrt{3} ) ( x^{3}+frac{1}{x^{3}}+3 sqrt{3}=3 sqrt{3} ) ( x^{3}+frac{1}{x^{3}}=0 ) ( therefore ) similary ( x^{55}+frac{1}{x^{55}}=0 )
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