Question

( quad 3=frac{1+i}{sqrt{2}} )
( Rightarrow quad quad quad quad^{2}=frac{(1+i)^{2}}{(sqrt{2})^{2}}=frac{1+i^{2}+2 i}{2}=frac{2 i}{2}=i )
( Rightarrowleft(3^{2}right)^{2}=3^{4}=i^{2}=-1 )
( Rightarrow frac{1929}{3^{8}}=left(3^{8}right)^{241} cdot 3=(1)^{241} cdot 3 )
( =frac{3}{17} )
Oprion (4)

# Assignme Objective Type Ques tive Type Questions (One option is correct) [Basic of Complex Numbers] 1+i If z= then the value of z1929 is (1) 1 +i (2) -1 7.

Solution