Assume that 10-17 J of light energy...
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Assume that 10-17 J of light energy is needed by the interior of the human eye to see an object. How many minimum photons of green light (. = 310 nm) are needed to generate this energy: (A) 14 (B) 15 (C) 16 (D) 17

JEE/Engineering Exams
Chemistry
Solution
139
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( n cdot n_{k} / lambda=10^{-17} ) n ( 2 frac{lambda cdot 10^{-1} A}{text { he }}=frac{310 times 10^{-9} times 10^{-17}}{60^{3} 3 times 10^{8} times 6.634 times 10^{-34}} ) ( frac{310}{3 times 6.624} ) ( =15.59 mathrm{m} 16 )
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