Question

( begin{array}{l}int frac{3}{(2-x)^{2}} d x tan (2-x)=t x-d x=d t x quad int frac{-3 cdot d t}{t^{2}} quad=-3 int frac{d t}{t^{2}} =-3left(frac{t^{-1}}{-1}right)+c & =frac{3}{t}+c=frac{3}{2-x}+cend{array} )

# B-1. J U X, (use, u = 2x2) B-2.a (sec2ttan 21 dt, (use, u = 21) integrate by using a suitable substitution B-3. Sex dx coction (c): Definite integration B-4. (sin(82-5) dz

Solution