Question

( eta(A)=110 quad n(A-B)=50 )
( n(B)=300 )
( n(A-B)=n(A cup B) )
( n(A cup B)=n(A)+n(B)-n(A cap B)-0(B) )
( n(A B)+n(B)=n(A)+n(B)-n(A cap B) )
( 50+300=110+300-n(A cap B) )
( n(A cap B)=410-350=60 )
Acconding, to eq ( 0 n(A cup B)=350 )

# B) equals • If n(A) = 110, n(B) = 300, n(A - B) = 50, then n( A

Solution