Question

( f(x)=y=frac{x-2}{x-3} )
( x y-3 y=x-2 )
( x y-x=3 y-2 )
( x(y-1)=34-2 )
( x=frac{3 y-2}{y-1} )
( 8-1(y)=frac{3 y-2}{y-1} )
( therefore f^{-1}(x)=frac{3 x-2}{x-1} )

# B f(x) = x-2, 43, examine whether x-3 invertible also find p! f(x) is

Solution