b-x 16-dx 63/2 – x3/2 6-8
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b-x 16-dx 63/2 – x3/2 6-8

JEE/Engineering Exams
Maths
Solution
105
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( frac{(sqrt{b}-sin )(sqrt{b}+sqrt{x})}{(sqrt{b}-sin )}=frac{b^{3 / 2}-x^{3 / 2}}{b-x} ) 3 ( (5 b+sqrt{x})(b-x)=b^{3 / 2}-x^{3 / 2} ) 3 ( 16^{3 / 2}-x sqrt{b}+b sqrt{x}-x^{3 / 2}=b^{3 / 2}-x^{3 / 2} ) ( Rightarrow quad b sqrt{x}=x sqrt{b} ) ( Rightarrow quad sqrt{b}=sqrt{x} ) ( Rightarrow x=b quad ) but ( x ) cant be ( b ) because denominater Cend be zere orivating "Nd solution. and sbeity. teld a pesonels what te a cestion ine a
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