Question

For a diabatic reversible expanticin [ q=0 text { of } W=n D T ]
For adiabatic proces ( quad P V^{4}= ) Com tant
[
begin{array}{c}
text { or } Pleft(frac{n R T}{P}right)^{Y}=text { contant }
therefore P^{1-4} T^{4}=text { constont }
therefore(16)^{1-y}(3 omega)^{4}=(1)^{1-4}(T)^{4}
end{array}
]
fiete for ( s O_{3} quad y=frac{c_{p}}{c_{v}}=frac{3}{3} )
[
therefore quad(16)^{-1 / 3}(3 omega)^{4 / 3}=(1)^{1 / 3}(tau)^{4 / 3}
]
( frac{(2 times 3 w)^{4 / 3}=}{sqrt{7-6+4}} )
[
begin{array}{l}
text { Fere }
T=150
end{array}
]

# besoa gas expanded adiabatically "G g poreibto Bom 16 atm 8 300 K to larm calularo final Temp. a 150 K 20000 30 250 K 4) 300 k

Solution