Question
Uiven the turo equalion ( 3 x+y=8 quad 8 quad x+y=6 )
Solue by substution method Let ( cdot 3 x+y=8 rightarrow 0 )
[
8 x+8=6 rightarrow(2)
]
( operatorname{lom}(2) cdot x+7=6 )
( frac{1}{2} )
( y=6-x )
Now, value obt ( y=6+x ) 'subtution in equation
Q we quet
[
3 x+6-x=8
]
( Rightarrow 2 x=8-6=2 )
[
x=1
]
8 Value of ( x=1 ) subtuting in
eavation
(2) wa get ( 1+y=6 )
( Rightarrow vec{sigma}=6-1 Rightarrow[y=5 )
So, ( x=1 quad & quad y=5 ), by sututionmel

by Substitution method find 3x +y = 8 and aty=6
Solution
