Question

( F sin theta=m a )
Firr
( 15 times frac{8}{5}=frac{89}{a=3 m / s^{2}} )
( tan theta

# C ) 5 A block B is tied to one end of a uniform rope R as shown. The mass of block is 2 kg and that of rope is 1 kg. A force F = 15 N is applied at angle 37° with vertical. The tension at the mid-point of rope is:- F 37° B (A) 1.5 N (B) 2 N (C) 3N (D) 4.5 N

Solution