Calculate the wavelength of the pho...
Question
Calculate the wavelength of the photon, which excites the electron of hydrogen atom from ground state to fourth energy level. lonization energy of hydrogen atom is 1
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Calculate the wavelength of the photon, which excites the electron of hydrogen atom from ground state to fourth energy level. lonization energy of hydrogen atom is ( 1312 mathrm{kJ} / mathrm{mol} ).

JEE/Engineering Exams
Chemistry
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Calculate the wavelength of the photon, which excites the electron of hydrogen atom from ground state to fourth energy level. lonization energy of hydrogen atom is 1312kJ/mol.
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Energy of nth orbit is given by ( mathrm{En}=-21.8 times 10^{-19} times mathrm{Z}^{2} / mathrm{n}^{2} )
If ( Z=1 ) then, ( E n=-21.8 times 10^{-19} / n^{2} ) J/atom
For fist orbit, ( mathrm{E}_{1}=-2.18 times 10^{-19} / 1^{2}=-21.8 times 10^{-19} mathrm{j} / ) atom
for 4 th orbit ( , E_{4}=-2.18 times 10^{-19} / 4^{2}=-1.36 times 10^{-19} mathrm{J} / ) atom
Now, ( Delta E=E_{4}-E_{1}=h c / lambda )
( -1.36 times 10^{-19}+2.18 times 10^{-19}=6.636 times 10^{-34} times 3 times 10^{8} / lambda )
( 2.04 times 10^{-19}=6.636 times 3 times 10^{-26} / lambda )
( lambda=97.3 mathrm{nm} )

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