Question

[
D=132 mathrm{km}
]
Passenger Irain Spled = ( x ) Express Irain speed ( =x+11 ) begin{tabular}{l|l}
Passenger & Express
( s=frac{d}{t} ) & ( t=frac{d}{s} )
( t=frac{132}{x} ) ho. & ( t=frac{132}{x+11} )
end{tabular}
( frac{132}{x}-frac{132}{x+11}=1 )
( 132 times 11=x(x+11) )
( 00 x^{2}+11 x-132 times 11=0 )
( 0^{circ} circ x=frac{-11 pm 77}{2}=frac{-44}{x} cdot frac{33}{3} )
Speed of passenger train ( =33 mathrm{km} / mathrm{k} )
[
begin{aligned}
operatorname{expres} theta &=x+11
&=44 mathrm{km} / mathrm{mr}
end{aligned}
]

# can separately fill the tank. 10. An express train takes '1 hour less than a passenger train to travel 132 km between Mysore and Bangalore (without taking into consideration the time they stop at intermediate stations). If the average speed of the express train is 11km/h more than that of the passenger train, find the average speed of the two trains

Solution