Question

The length increases by ( 4 % ) and ( g ) increases by ( 2 % )
Using the formula of time period of simple pendulum
( T=2 pi sqrt{frac{l}{g}} )
According to question
The time period of simple pendulum
( T^{prime}=2 pi sqrt{frac{1.04 l}{1.02 g}} )
( T^{prime}=sqrt{frac{1.04}{1.02} T} )
Using the formula of percentage error
( bar{T}=frac{T^{prime}-T}{T} )
( frac{Delta T}{T}=frac{sqrt{frac{1.04}{1.02}} T-T}{T} )
( frac{Delta T}{T}=sqrt{frac{1.04}{1.02}}-1 )
( frac{Delta T}{T}=0.009 )
( frac{Delta T}{T} times 100=0.9=1 % )
Hence, The time period of simple pendulum is Increases by ( 1 % )

# ce 21. In a simple pendulum, length increases by 4% and g increases by 2%, then time period of simple pendulum (1) Increases by 4% (2) Increases by 3% sured cm is (3) Decreases by 3% cimum (4) Increases by 1%

Solution