Column-11 (P) - 1 (0) 1 [MATRIX MAT...
Question  # Column-11 (P) - 1 (0) 1 [MATRIX MATCH TYPE] Column- (4) If a =3[18+277-8-27), b = (42) (30) +36. then the value of log b is equal to (B If a = 14 +23-14-23.b = V11+6V-VI-6v2. then the value of log bis equal to (C) If a=v3+23.6=v3-23. then the value of logb is equal to If a=v7+72-1,b=V7-172-1.then then the value of log bis equal to The number of zeroes at the end of the product of first 20 prime numbers, is (F) The number of solutions of 22-3-= 55, in which x and y are integers, is (T) None

JEE/Engineering Exams
Maths
Solution 30 4.0 (1 ratings)  (b) ( a=sqrt{4+2 sqrt{3}}-sqrt{4 cdot 2 sqrt{3}} ) ( =sqrt{(sqrt{3}+1)^{2}}-sqrt{(3-1)^{2}} ) ( =left(frac{sqrt{3}+1}{2}right)-(5 x+2) ) ( b=sqrt{11+6 sqrt{2}}-sqrt{11-6 sqrt{2}} ) ( =sqrt{(3+sqrt{2})^{2}}-5(3-sqrt{2})^{2} ) ( =3+sqrt{2}-3+sqrt{2} ) ( =2 sqrt{2} ) ( log _{2} 2 sqrt{2}=3 / 2(5) ) (0) ( a=sqrt{3+2 sqrt{2}}=sqrt{3}+sqrt{2}+1 ) ( b=sqrt{3-25}=sqrt{3}-sqrt{2}-1 times frac{sqrt{2}+1}{sqrt{2}+1}=frac{1}{sqrt{2}+1} ) ( therefore log _{a} b=log _{h+1}(sqrt{2+1})^{-1}=-1 ) a) ( a=(2+sqrt{3}) ) ( b=(2-sqrt{3}) quad therefore log _{a} b=-1 ) Quick and Stepwise Solutions Just click and Send OVER 20 LAKH QUESTIONS ANSWERED Download App for Free