Question
( begin{array}{l}cos cos (pi-theta)=-cos theta cot left(frac{pi}{2}+thetaright)=-tan theta quad cos (-theta)=cos theta sin (2 pi-theta)=-sin thetaend{array} tan left(frac{3 pi+theta}{2}right)=-tan theta )
( frac{-. cos (pi-theta) cdot cot left(frac{3 pi+theta}{2}right) cdot cos (-theta)}{tan (pi+theta) cdot tan left(frac{3 pi}{2}+thetaright) cdot sin (2 pi-theta)} )
( =frac{-cos theta cdot-tan theta cdot cos theta}{tan theta-cot theta cdot sin theta} )
( frac{=cos ^{2} Q}{sin theta frac{cos 6}{pi}}=cos theta cdot operatorname{vin} e d n )

Cos (1-0). Cot (I 16). Costa) tan (a to i tan ( 3t to). Sin G2-0 =COSO.
Solution
