Question

given ( : 10 x+y=5(x+y) )
( 5 x-4 y=0 )
Also ( 10 x+y=5+2 x y )
putting ( mathrm{y}=5 mathrm{x} / 4 ) from equation (1)
( 10 x+5 x / 4=5+2 x(5 x / 4) )
( (45 x) / 4=5+left(5 x^{2}right) / 2 )
( 45 x=20+10 x^{2} )
( 10 x^{2}-45 x+20=0 )
( 2 x^{2}-9 x+4=0 )
( (x-4)(2 x-1)=0 )
hence ( x=4 ) or ( 1 / 2 )
but ( x ) is an integer. so ( x=4 )
( y=5 x / 4=5 )
the number is ( 10 x+y=40+5=45 )

# CPU ICDSL-DUM-2004 A two digit number is 5 times the sum of its digits and is also equal to 5 more than twice the product of its digits. Find the number. (CBSE-Delhi-2004C) The cum of two numbers a and bis 15. and the sum of their recindacale 1 .3 Tind

Solution