Question

cuhen 223+*+ Kx-6 ů divided by 2.6 the demainder is 36. find the value of

11th - 12th Class

Maths

Solution

117

4.0 (1 ratings)

( f(x)=2 x^{3}+x^{2}+k x-6 ) if aveded thy ( x-3 ) there bemender ix 36 i.e ( f(x=3)=36 ) ( S_{0} Rightarrow 2(3)^{3}+3^{2}+k(3)-6=36 ) ( 2(27)+9+3 k-6=36 ) [ begin{aligned} 63-6+3 k &=36 3 k &=36-57 end{aligned} ] valueds ( k quad(x-7) ) ( 3 x=-21 ) ( k= )