Question

free body diagram: ( tan alpha=frac{a_{A}}{a_{B}} quad alpha=37^{circ} )
[
begin{aligned}
frac{n omega omega}{0}: & m_{A} g-N cos alpha=m_{A} a_{A}
& N sin alpha=m_{B} a_{B}
end{aligned}
]

# D-5. Find the acceleration of rod A and wedge B in the arrangement shown in figure if the mass of rod equal that of the wedge and the friction between all contact surfaces is negligible and rod A is free to move downwards only. Take angle of wedge as 370, 37

Solution