Question

(i) Mass of one electron ( =9.11 times 10^{-31} mathrm{kg} ) ( therefore 1 mathrm{g}=10^{-3} mathrm{kg}=left(1 / 9.11 times 10^{-31}right) times 10^{-3} ) electrons
( =1.09^{8} times 10^{27} )
(ii) Mass of one electron ( =9.11 times 10^{-31} mathrm{kg} )
( therefore ) Mass of 1 mole of electrons ( =left(9.11 times 10^{-}right. )
31)( timesleft(6.022 times 10^{23}right)=5.48 times 10^{-7} mathrm{kg} )
Charge on one electron ( =1.602 times 10^{-19} ) coulomb
( therefore ) Charge on 1 mole of electrons ( =left(1.602 times 10^{-}right. ) ( 19 timesleft(6.022 times 10^{23}right)=9.65 times 10^{4} ) coulombs.

# DA URCISES V (1) Calculate the number of electrons which will together weigh one gram. (11) Calculate the mass and charge of one mole of electrons. (i) Calculate the total number of electrons present in one mole of mothon 2.2

Solution