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frac{tan(A-B)+tanB}{1-tan(A-B).tanB}=tanA L.H.Sfrac{tan(A-B)+tanB}{1-tan(A-B)tanB}=tan(A-B+B) =tanA R.H.SBecause tan(A+B)=frac{tanA+tanB}{1-tanA+tanB}