Question
SHREE NAVNEET
( (x+y+1) frac{d y}{d x}=1 )
( frac{d y}{d x}=frac{1}{x+y+1} )
( frac{d x}{d y}=x+y+1 )
( 9+18 ) a linear
( e q )
( frac{d x}{d y}-x=y+1 )
gf is the formof ( frac{d x}{d y}+P x=0 )
then Integrating factor ( =e^{int p d y}=e^{-y} )
hence sol.
( x cdot I cdot f cdot=int Q cdot I cdot f cdot d y+c )
( x cdot e^{-y}=int(y+1) cdot e^{-y} d y+c )
( e^{-y} cdot x=-e^{-y}(y+1)-e^{-y}+c )
( x=c cdot e^{y}-(y+2) )
( x+(y+2)=c cdot e )

des al 10. (x + y + 1) = 1. Ans.-> x=c (+2) tan 11
Solution
