Question

( 9 cdot 1 times 10^{-31} mathrm{kq}=100 times 10^{19} mathrm{c} )
( frac{mathrm{kg}}{9}=frac{1.6 times 10^{+4}}{9.1 times 10^{-3}} cdot 0 )
( 2.0 .5 times 10^{14} mathrm{e} )

# determine the charge of 300 kg of electrons

Solution