Question

( f(x)=frac{|x-3|}{x-3} )
( x eq 3, ) becour ( x ) at ( x=3 )
( f(x)=frac{x-3}{x-3}=1 )
( f(x)<3=frac{-(x-3)}{(x-3)}=-1 mid begin{array}{c}30 R-1+3} {[1,-1]}end{array} )

# Domain range 23/ Domain and range of f(x) = 1*—3| X-3 are are respectively (a) R,[-1,1] , (b) R-{-3},{1, -1} (d) None of these C) RR

Solution