Question

Doust (a) 23.48 eace occuit of t (d) 1 da) 4 (6) 3 (c) 2. The percentage of P,0, in diammonium hydrogen phosphate, ((NH4)2 HPO4] is: (b) 46.96 (c) 53.78 (d) 71.00 of nitrogen in urea NH.CONH) is:

JEE/Engineering Exams

Chemistry

Solution

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( 2left(mathrm{NH}_{4}right)_{2} mathrm{HPO}_{4} Rightarrow mathrm{P}_{2} mathrm{O}_{5} ) 2 moles of diammonium hydrogen phosphate, yield 1 mole of ( mathrm{P}_{2} mathrm{O}_{5} ) The molar mass of ( left(mathrm{NH}_{4}right)_{2} mathrm{HPO}_{4} ) is given by ( = ) ( =36+1+31+44 ) ( =132 mathrm{g} ) Molar mass of ( mathrm{P}_{2} mathrm{O}_{5} ) is given by ( = ) ( =62+80 ) ( =142 mathrm{g} ) So, percentage of ( mathrm{P}_{2} mathrm{O}_{5} ) is ( =[142 /(2) times 132] times 100 ) ( =142 / 264 times 100 ) ( =53.78 % ) Therefore percentage of ( mathrm{P}_{2} mathrm{O}_{3} ) is ( 53.78 % )