Question
( frac{d y}{d x}+frac{1+cos 2 y}{1-cos 2 x}=0 )
( 1+cos 2 y=2 cos 2 y )
( 1-cos 2 x=2 sin 2 x )
( therefore frac{d y}{d x}+frac{2 cos 2 y}{x sin ^{2} x}=0 )
( 28 e^{2 x} y cdot d y=-operatorname{cosec}^{2} x cdot d x )
What ong
( tan (y)=cot (x) )
( left.therefore y=tan ^{-1}[cot x)right] )

dy dx - +- 1+cos 2y 1- cos 2x = 0
Solution
