Question

dy dx - +- 1+cos 2y 1- cos 2x = 0

JEE/Engineering Exams

Maths

Solution

209

4.0 (1 ratings)

( frac{d y}{d x}+frac{1+cos 2 y}{1-cos 2 x}=0 ) ( 1+cos 2 y=2 cos 2 y ) ( 1-cos 2 x=2 sin 2 x ) ( therefore frac{d y}{d x}+frac{2 cos 2 y}{x sin ^{2} x}=0 ) ( 28 e^{2 x} y cdot d y=-operatorname{cosec}^{2} x cdot d x ) What ong ( tan (y)=cot (x) ) ( left.therefore y=tan ^{-1}[cot x)right] )