Question

( log _{a}(a b)=x Rightarrow log _{a} a+log _{a} b=x Rightarrow log _{a} b=x-1 )
( Rightarrow log _{b} a=frac{1}{x-4} Rightarrow log _{b} a+1=frac{1}{x-4}+1 )
( Rightarrow log _{b} a+log _{b} b=frac{1+x-q}{x-a} )
( Rightarrow log _{b} a b=frac{1+x-d}{x-d}=frac{x}{x-4}=frac{x}{x-1} )

# E-7. If log (ab) = x, then log, (ab) is equal to (A) (C), + X 1- x

Solution