E log(logi12x– 31097/2 X+5) = 2

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( log _{1 / 2}^{2} x-3 log _{1 / 2} x+5=9 ) ( Rightarrow ) Let ( log _{1 / 2} x=t ) ( Rightarrow quad t^{2}-3 t-4=0 ) ( Rightarrow(t-4)(t+1)=0 ) ( t=4,-1 ) ( therefore log _{1 / 2} n=4 quad operatorname{sing}_{1 / 2} x=-1 ) ( therefore x=frac{1}{16} quad operatorname{arc} 2 quad sin 3 )

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