EQUATION OF CIRU CENTRE -RADIUS FOR...
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EQUATION OF CIRU CENTRE -RADIUS FORM The equation of the circle with radius 3 and centre as the point of intersection of the lines 2x + 3y =5,2x - y =1 is 1) x² + y² = 9 2) x² + y2 - 2x - 2y— 7 = 0 3) x² + y2 - 2x - 2y + 7 = 0 4) x² + 3 +9=0

JEE/Engineering Exams
Maths
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Point of intersechon of ( -2 x+3 y+5=0 ) Point of intasection ob ( 2 x+3 y=5 rightarrow 0 ) [ text { & } 2 x-y=1 quad rightarrow text { (2) } ] ( sqrt{3} ) Centre is (1,1) [ begin{array}{l} 4 y=4 y=1 end{array} text { and }[x=1 ] Qincle equ will be [ (x-1)^{2}+(y-1)^{2}=3^{2} ] ( Rightarrow quad x^{2}-2 x+1+y^{2}-2 y+1=9 ) 3 [ x^{2}+y^{2}-2 x-2 y-7=0 ]
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