Question

Point of intersechon of ( -2 x+3 y+5=0 )
Point of intasection ob ( 2 x+3 y=5 rightarrow 0 )
[
text { & } 2 x-y=1 quad rightarrow text { (2) }
]
( sqrt{3} )
Centre is (1,1)
[
begin{array}{l}
4 y=4
y=1
end{array} text { and }[x=1
]
Qincle equ will be
[
(x-1)^{2}+(y-1)^{2}=3^{2}
]
( Rightarrow quad x^{2}-2 x+1+y^{2}-2 y+1=9 )
3
[
x^{2}+y^{2}-2 x-2 y-7=0
]

# EQUATION OF CIRU CENTRE -RADIUS FORM The equation of the circle with radius 3 and centre as the point of intersection of the lines 2x + 3y =5,2x - y =1 is 1) x² + y² = 9 2) x² + y2 - 2x - 2y— 7 = 0 3) x² + y2 - 2x - 2y + 7 = 0 4) x² + 3 +9=0

Solution