er - Daily Practi With a concave, m...
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er - Daily Practi With a concave, mirror, an object is placed at a distance X, from the principal focus, on the principal ax image is formed at a distance X2 from the principal focus. The focal length of the mirror is a) X,X2 6) +*2 d) VX2 V2

JEE/Engineering Exams
Physics
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Object distance, ( u=-(x 1+f) ) Image distance, ( v=-(x 2+f) ) Focal length,F=-f Using mirror formula, ( 1 / v+1 / u=1 / F ) ( -1 /(x 2+f)-1 /(x 1+f)=-1 / f ) On solving, we get ( f=sqrt{x_{1} x_{2}} )
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