Question

Sol. ( (1) 12(3 operatorname{men}+4 text { boys })=10(4 operatorname{men}+3 text { boys }) )
( Rightarrow 36 mathrm{men}+48 ) boys ( =40 mathrm{men}+30 ) boys
( Rightarrow 4 mathrm{men}=18 ) boys
or ( 2 mathrm{men}=9 ) boys
( therefore 4 mathrm{men}+3 ) boys
( =21 ) boys who do the work in 10 days
and, 2 men +3 boys ( =12 ) boys
( therefore quad mathrm{M}_{1} mathrm{D}_{1}=mathrm{M}_{2} mathrm{D}_{2} )
( Rightarrow 21 times 10=12 times mathrm{D}_{2} )
( Rightarrow mathrm{D}_{2} )
( =frac{21 times 10}{12}=frac{35}{2}=17 frac{1}{2} ) days

# EX.3.3 men and 4 boys can complete and 4 boys can complete a piece of work m 12 days, 4 men and 3 boys can do the same work in 10 days. Then 21 finish the work in number of days is SSC CGL (Tier-I) 2012 Can (1) 17.days (2) 5 days (4) 22 days (3) 8 days

Solution