Question

Sol. (2) ( x=frac{cos theta}{1-sin theta}=frac{cos theta(1+sin theta)}{(1-sin theta)(1+sin theta)} )
( =frac{cos theta(1+sin theta)}{1-sin ^{2} theta} )
( =frac{cos theta(1+sin theta)}{cos ^{2} theta}=frac{1+sin theta}{cos theta} )
( therefore frac{cos theta}{1+sin theta}=frac{1}{x} )

# Ex.3. If x = cos 0 1-sin , then the cos 1+ sin is equal to SSC CGL Tier-I 2014 1 (1) -1 (2) (3) 24 x +1

Solution