Ex.4. I is the incentre of A ABC, ZABC = 60° and ZACB = 50°. Then Z BIC is : (1) 55° (2) 125° (3) 70° (4) 65°

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( angle mathrm{ABC}=60^{circ}, mathrm{ACB}=50^{circ} ) ( angle mathrm{IBC}=frac{1}{2} angle mathrm{ABC}=30^{circ} ) ( angle mathrm{ICB}=frac{1}{2} angle mathrm{ACB}=25^{circ} ) ( therefore angle B I C=180^{circ}-30^{circ}-25^{circ}=125^{circ} )

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