Question

( f(y=2 x )
( R={(1,2)(2,4)(3,6)(4,8), ldots ldots-3 )
Then, Domain ( rightarrow ) all naturas humbers
( (N) )
Range ( rightarrow ) all evern number. yes, thin relatim is a frometim.

# Example 1.9 Given f(x) = 2x - r', find (i)f(1) (ii) f(x+1) (iii) f(x) + f(1) Solution (i) Replacing x with 1, we get f(1) = 2(1) - (1) =2-1=1 (ii) Replacing x with x+1, we get f(x+1) = 2(x + 1) - (x + 1) =2x +2 - (z? +22 +1) =- (iii) f(x) + f(1) = (2x – xº)+1=-x? + 2x +1 [Note that f(x) + f(1)= f(x + 1). In general f(a+b) is not equal to Exercise 1.3 1. Let f = {(x, y) | X,Y E N and y= 2x} be a relation on N. Find the and range. Is this relation a function? 2. Let X= {3,4,6,8). Determine whether the relation R = {(x, f(x)) is a function from X to N? бпіка andex Title Page No. Teacher's Sign/ Remarks பருக 2h

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