Question
soLUTION We have
[
begin{aligned}
L H S &=tan ^{-1}left(frac{cos x}{1+sin x}right)
&=tan ^{-1}left{frac{sin left(frac{pi}{2}-xright)}{1+cos left(frac{pi}{2}-xright)}right}
&=tan ^{-1}left{frac{2 sin left(frac{pi}{4}-frac{x}{2}right) cos left(frac{pi}{4}-frac{x}{2}right)}{2 cos ^{2}left(frac{pi}{4}-frac{x}{2}right)}right}
therefore tan ^{-1}left(frac{cos x}{1+sin x}right)=left(frac{pi}{4}-frac{x}{2}right) & text { tan }left.left(frac{pi}{4}-frac{x}{2}right)right}=left(frac{pi}{4}-frac{x}{2}right)=text { RHS. }
end{aligned}
]

EXAMPLE 28 Prove that tan cOS X (1 + sin x
Solution
