Question

(11) let ( x=0.003232 )
Then ( 100 x=0.3232 )
& ( 10000 x=32 cdot 32 )
( begin{aligned} Rightarrow 10000 x-100 x &=32.32-0.3232 text { or } quad 9900 x &=32 therefore x &=frac{32}{9900} end{aligned} )
( therefore 0.003232=frac{32}{9900}left(operatorname{in} frac{1}{2} 100 mright) )
(1) let ( x=0 cdot 134 )
( therefore quad 0 cdot overline{13} y=frac{133}{990}(text { in } 1 / 2,10 mathrm{m}) )

# Express in plq farm 0.134 < 0.003232

Solution