Question

Sol. ( (4) x^{2}+frac{1}{x^{2}}=2 sin left(frac{pi x}{2}right) )
( Rightarrowleft(x-frac{1}{x}right)^{2}+2=2 sin left(frac{pi}{2}right) )
( left(x-frac{1}{x}right)^{2}+2=2 )
( Rightarrow quad x-frac{1}{x}=0 quad[because sin theta leq 1] )

# Ez.2.12 sin () -x * . then the value of [x - 5) is (1)-1 (3) 1 SSC CGL (Tier-I) 2012 (2) 2 (4) O

Solution