Question

31. ( ( 2) ) Given, ( cot A=frac{12}{5} ) then by Pythagoras
Then ratio
[
begin{aligned}
sin A &=frac{5}{13}
cos A &=frac{12}{13} text { and } operatorname{cosec} A=frac{13}{12}
end{aligned}
]
Put the values in given question ( (sin A+cos A) times operatorname{cosec} A )
[
left(frac{5}{13}+frac{12}{13}right) times frac{13}{12}=frac{17}{12}
]

# f. cotA= en 31. If cot at then (sin A +cos A) cosec A is? RRB NTPC (Phase I) 2016 (1) (2) (3) (4) 2

Solution