Question

( c^{2}-30+underline{90}=60 )
( Rightarrow quad 60+30=underline{20} )
( (11)(-52)+(-52)=-104 )
( Rightarrow )
( -52-52=-104 )
( N_{1}(40+(-70)=70 )
( 75+(-25)=50 )
( operatorname{ing}[(-3)+(-12)]+(-77)=-+[-12-7] )
( -15-77=frac{-3}{=}+(-89) )
( x y-42+left[frac{60}{4}+(-23)right]=[-715]+3 )
( therefore-42+x-23=x+15+x )
( -65=15+x )
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# Fill in the blanks (0) (-30)+_ - 60 (ili) (-52)+(-52) - (W) +(-70) - 70 (vii) 75+(-25) (ix) [(-3)+(-12)]+(-77)= __ +[(-12)+(-77)]. (x) (-42)+[_+(-23)] = __+15]+

Solution