Question
Molar mass of ammonia is ( 17 mathrm{g} ). So ( 17 mathrm{g} ) ammonia contains ( 6.022 times 10^{wedge} 23 ) number of
ammonia molecules.
So 4.25 g ammonia will contain ( left(6.022 times 10^{wedge} 23 times 4.25right) / 17=1.5 times 10^{wedge} 23 ) number of ammonia molecules. Each molecule contain 4 atoms ( (1 mathrm{N} text { atom and } 3 mathrm{H} ) atoms). So ( 4.25 mathrm{g} ) ammonia will contain ( 1.5 times 10^{wedge} 23 times 4=6 times 10^{wedge} 23 ) number of atoms.

Find no of atoms in 4.25 g of NH3 classe Date Page
Solution
