Find Possible valves of expression ...
Question
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Find Possible valves of expression x2

JEE/Engineering Exams
Maths
Solution
103
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Possible values of 1x2+2= RANGE of 1x2+2 So let 1x2+2=y =yx2+2y=1 yx2+2y-1=0 D=b2-4ac=024(y)(2y-1) =-4y(2y-1) For x to be real D>0 -4y(2y-1)>0 4y(2y-1)<0 y(2y-1)<0 Graph of above function is y0, 12 Range of 1x2+2is (0,12) 

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