Question

Find the general solution of 6 when tan20 – (1 +13) tan 0 + 13 = 0 (A) nn + & nn+ , nel (B) na +" & na +, nel (C) (2n + 1) * & nn+nel TT (D) None of these

JEE/Engineering Exams

Maths

Solution

140

4.0 (1 ratings)

( tan ^{2} theta-tan theta-int 3 tan theta+int 3=0 ) ( tan theta(k operatorname{an} theta-1)-sqrt{3}(tan theta-1)=0 ) ( tan theta=sqrt{3} cos theta=1 ) ( theta=n pi+frac{pi}{3} quad theta=n pi+frac{pi}{4} )