Question

[
begin{array}{l}
f(x)=frac{x+1}{n} quad[1,3)
f(1)=2 quad f(3)=10 / 3
end{array}
]
( f^{prime}=frac{f(3)-f(1)}{2}=frac{frac{10}{2}-2}{2}=frac{4}{3-2}=frac{2}{3} )
( f^{prime}(x)=frac{1-1}{x^{2}} )
( =1 cdot 7 )
to LMNT ( =frac{2}{3} ) is mininualig arcolding to for

# Find the lagrante snean value them in abblicable to the function الكركم + لايك

Solution